What is 2x^2-5x=x^2+3x-k(x)+1 ?

The solution to 2x^2-5x=x^2+3x-k(x)+1 is Parabola with (h,k)=(4,17),p=-1/4

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2x^2-5x=x^2+3x-k(x)+1

2 x^{2} - 5 x = x^{2} + 3 x - k (x) + 1

(h, k) = (4, 17), p = - \frac{1}{4}

Solution steps

2 x^{2} - 5 x = x^{2} + 3 x - y + 1

Rewrite

2 x^{2} - 5 x = x^{2} + 3 x - y + 1

in the standard form

4 (- \frac{1}{4}) (y - 17) = (x - 4)^{2}

Therefore parabola properties are:

(h, k) = (4, 17), p = - \frac{1}{4}

3 y^{2} - 6 x = 0

x^{2} - 10 x + 8 y + 33 = 0

y^{2} = 20 (x - 10)

8 \frac{m ( x )}{4} m (x) = x

x^{2} + 6 x + 8 y + 1 = 0

What is 2x^2-5x=x^2+3x-k(x)+1 ?
The solution to 2x^2-5x=x^2+3x-k(x)+1 is Parabola with (h,k)=(4,17),p=-1/4