What is ((x+1)^2)/4+((y+1)^2)/9 =1 ?

The solution to ((x+1)^2)/4+((y+1)^2)/9 =1 is Ellipse with (h,k)=(-1,-1),a=2,b=3

Popular >

((x+1)^2)/4+((y+1)^2)/9 =1

\frac{( x + 1 ) ^{2}}{4} + \frac{( y + 1 ) ^{2}}{9} = 1

(h, k) = (- 1, - 1), a = 2, b = 3

Solution steps

\frac{( x + 1 ) ^{2}}{4} + \frac{( y + 1 ) ^{2}}{9} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{4} + \frac{( y + 1 ) ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{2 ^{2}} + \frac{( y - ( - 1 ) ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, - 1), a = 2, b = 3

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 1, - 1), b = 3, a = 2

\frac{( x - 3 ) ^{2}}{4 ^{2}} + \frac{( y + 2 ) ^{2}}{3 ^{2}} = 1

\frac{( x ) ^{2}}{25} + \frac{( y ) ^{2}}{16} = 1

\frac{x ^{2}}{256} + \frac{y ^{2}}{400} = 2

3 x^{2} + 4 y^{2} + 6 x - 24 y + 27 = 0

25 x^{2} + 9 y^{2} - 100 x + 18 x - 10 y - 31 = 0

What is ((x+1)^2)/4+((y+1)^2)/9 =1 ?
The solution to ((x+1)^2)/4+((y+1)^2)/9 =1 is Ellipse with (h,k)=(-1,-1),a=2,b=3