What is (x^2)/(16)+(y^2)/((4-16))=1 ?

The solution to (x^2)/(16)+(y^2)/((4-16))=1 is Ellipse with (h,k)=(0,0),a=4,b=2sqrt(3)i

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(x^2)/(16)+(y^2)/((4-16))=1

\frac{x ^{2}}{16} + \frac{y ^{2}}{( 4 - 16 )} = 1

(h, k) = (0, 0), a = 4, b = 23 i

Solution steps

\frac{x ^{2}}{16} + \frac{y ^{2}}{4 - 16} = 1

Rewrite

\frac{x ^{2}}{16} + \frac{y ^{2}}{4 - 16} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 3 i ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 23 i

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 4, b = 23 i

9 x^{2} + y^{2} - 100 = 0

9 x^{2} + 16 y^{2} + 180 x - 256 y - 452 = 0

9 x^{2} + 6 y^{2} = 54

\frac{( ( x - 4 ) ^{2} + y ^{2} )}{( x - 1 ) ^{2}} = \frac{1}{3}

x^{2} + 9 y^{2} - 2 x - 72 y + 136 = 0

What is (x^2)/(16)+(y^2)/((4-16))=1 ?
The solution to (x^2)/(16)+(y^2)/((4-16))=1 is Ellipse with (h,k)=(0,0),a=4,b=2sqrt(3)i