What is 1=x^2+(y^2)/4 ?

The solution to 1=x^2+(y^2)/4 is Ellipse with (h,k)=(0,0),a=1,b=2

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1=x^2+(y^2)/4

1 = x^{2} + \frac{y ^{2}}{4}

(h, k) = (0, 0), a = 1, b = 2

Solution steps

1 = x^{2} + \frac{y ^{2}}{4}

Rewrite

1 = x^{2} + \frac{y ^{2}}{4}

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 1, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 2, a = 1

\frac{x ^{2}}{100} + \frac{y ^{2}}{25} = 16

\frac{( x + 5 ) ^{2}}{25} + \frac{( y + 4 ) ^{2}}{9} = 1

\frac{( ( x + 1 ) ^{2} )}{( 9 )} + \frac{( ( y - 2 ) ^{2} )}{( 4 )} = 1

25 xx + 9 yy - 18 y - 216 = 0

2 x^{2} + 5 y^{2} = 14

What is 1=x^2+(y^2)/4 ?
The solution to 1=x^2+(y^2)/4 is Ellipse with (h,k)=(0,0),a=1,b=2