What is ((x^2)/(a^2))+((y^2)/(b^2))=1 ?

The solution to ((x^2)/(a^2))+((y^2)/(b^2))=1 is Ellipse with (h,k)=(0,0),a=a,b=b

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((x^2)/(a^2))+((y^2)/(b^2))=1

(\frac{x ^{2}}{a ^{2}}) + (\frac{y ^{2}}{b ^{2}}) = 1

(h, k) = (0, 0), a = a, b = b

Solution steps

\frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} = 1

Rewrite

\frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{a ^{2}} + \frac{( y - 0 ) ^{2}}{b ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = a, b = b

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = a, b = b

14 x^{2} + 11 y^{2} - 252 x - 22 y + 991 = 0

\frac{( x + 4 ) ^{2}}{16} + \frac{( y - 5 ) ^{2}}{25} = 1

\frac{y ^{2}}{9} = 1 - \frac{x ^{2}}{4}

8 = \frac{1}{2} x^{2} + \frac{1}{4} y^{2}

\frac{( x - 2 ) ^{2}}{25} + \frac{( y - 2 ) ^{2}}{16} = 1

What is ((x^2)/(a^2))+((y^2)/(b^2))=1 ?
The solution to ((x^2)/(a^2))+((y^2)/(b^2))=1 is Ellipse with (h,k)=(0,0),a=a,b=b