What is y^2+(x^2)/4 =1 ?

The solution to y^2+(x^2)/4 =1 is Ellipse with (h,k)=(0,0),a=2,b=1

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y^2+(x^2)/4 =1

y^{2} + \frac{x ^{2}}{4} = 1

(h, k) = (0, 0), a = 2, b = 1

Solution steps

y^{2} + \frac{x ^{2}}{4} = 1

Rewrite

y^{2} + \frac{x ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 1

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 2, b = 1

f, f = 3 - x f (x)^{- 1} (x)

\frac{( x + 3 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{25} - 1 = 0

\frac{( x - 4 ) ^{2}}{4} + \frac{( y + 2 ) ^{2}}{9} = 1

\frac{x ^{2}}{4} + \frac{y ^{2}}{4 - 16} = 1

\frac{x ^{2}}{2} + \frac{y ^{2}}{a - 16} = 1

What is y^2+(x^2)/4 =1 ?
The solution to y^2+(x^2)/4 =1 is Ellipse with (h,k)=(0,0),a=2,b=1