What is 49x^2+y^2-14y=0 ?

The solution to 49x^2+y^2-14y=0 is Ellipse with (h,k)=(0,7),a=1,b=7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

49x^2+y^2-14y=0

49 x^{2} + y^{2} - 14 y = 0

(h, k) = (0, 7), a = 1, b = 7

Solution steps

49 x^{2} + y^{2} - 14 y = 0

Rewrite

49 x^{2} + y^{2} - 14 y = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 7 ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 7), a = 1, b = 7

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 7), b = 7, a = 1

\frac{x ^{2}}{9} + \frac{y ^{2}}{16} = 4

x^{2} + 5 y^{2} = 2021 y

(x + y) - x^{2} = x^{2} + y^{2}

64 x^{2} + 81 y^{2} = 81

9 x^{2} + 16 y^{2} = 4

What is 49x^2+y^2-14y=0 ?
The solution to 49x^2+y^2-14y=0 is Ellipse with (h,k)=(0,7),a=1,b=7