What is 6x+2x^2-5y+8=0 ?

The solution to 6x+2x^2-5y+8=0 is Parabola with (h,k)=(-3/2 , 7/10),p= 5/8

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6x+2x^2-5y+8=0

6 x + 2 x^{2} - 5 y + 8 = 0

(h, k) = (- \frac{3}{2}, \frac{7}{10}), p = \frac{5}{8}

Solution steps

6 x + 2 x^{2} - 5 y + 8 = 0

Rewrite

6 x + 2 x^{2} - 5 y + 8 = 0

in the standard form

4 \cdot \frac{5}{8} (y - \frac{7}{10}) = (x - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{2}, \frac{7}{10}), p = \frac{5}{8}

8 x^{2} = 12 y

(x + 4)^{2} = - 8 (y - 3)

x + (y - 3)^{2} = 0

x^{2} = y + 4

- x^{2} + y < 4

What is 6x+2x^2-5y+8=0 ?
The solution to 6x+2x^2-5y+8=0 is Parabola with (h,k)=(-3/2 , 7/10),p= 5/8