What is 0=4-4x^2-y^2 ?

The solution to 0=4-4x^2-y^2 is Ellipse with (h,k)=(0,0),a=1,b=2

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0=4-4x^2-y^2

0 = 4 - 4 x^{2} - y^{2}

(h, k) = (0, 0), a = 1, b = 2

Solution steps

0 = 4 - 4 x^{2} - y^{2}

Rewrite

0 - 4 + 4 x^{2} + y^{2} = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 1, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 2, a = 1

\frac{9 ( y ^{2} - 2 )}{16} + z^{2} = 1

x^{2} + y^{2} - 2 y + 1 = 1

\frac{1}{2} x^{2} + \frac{1}{3} y^{2} + \frac{1}{5} x - 6 x + 8 y + 2 - x = 0

x^{2} + 2 y + y^{2} < 0

x^{2} + (y - 1)^{2} = 1 - x^{2} - y^{2}

What is 0=4-4x^2-y^2 ?
The solution to 0=4-4x^2-y^2 is Ellipse with (h,k)=(0,0),a=1,b=2