What is ((x^2))/4+((y^2))/9 =1 ?

The solution to ((x^2))/4+((y^2))/9 =1 is Ellipse with (h,k)=(0,0),a=2,b=3

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((x^2))/4+((y^2))/9 =1

\frac{( x ^{2} )}{4} + \frac{( y ^{2} )}{9} = 1

(h, k) = (0, 0), a = 2, b = 3

Solution steps

\frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 1

Rewrite

\frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 3

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 3, a = 2

x^{(2)} + 4 x + 4 y^{(2)} - 6 y + 9 = 3

\frac{( x + 2 ) ^{2}}{5 ^{2}} + \frac{( y - 3 ) ^{2}}{3 ^{2}} = 1

\frac{( x - 5 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{25} = 1

\frac{( x - 2 ) ^{2}}{3 ^{2}} + \frac{( y - ( - 1 ) ) ^{2}}{2 ^{2}} = 1

16 x^{2} - 96 x + 9 y^{2} = 0

What is ((x^2))/4+((y^2))/9 =1 ?
The solution to ((x^2))/4+((y^2))/9 =1 is Ellipse with (h,k)=(0,0),a=2,b=3