What is ((x^2)/(64))+((y^2)/(36))=1 ?

The solution to ((x^2)/(64))+((y^2)/(36))=1 is Ellipse with (h,k)=(0,0),a=8,b=6

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((x^2)/(64))+((y^2)/(36))=1

(\frac{x ^{2}}{64}) + (\frac{y ^{2}}{36}) = 1

(h, k) = (0, 0), a = 8, b = 6

Solution steps

\frac{x ^{2}}{64} + \frac{y ^{2}}{36} = 1

Rewrite

\frac{x ^{2}}{64} + \frac{y ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{8 ^{2}} + \frac{( y - 0 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 8, b = 6

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 8, b = 6

X^{2} + 2 \cdot Y^{2} - 2 \cdot X - 4 \cdot Y - 8 = 0

\frac{x ^{2}}{21} + \frac{y ^{2}}{25} = 1

4 x^{2} + 16 y^{2} + 16 x + 160 y + 352 = 0

y^{2} = \frac{1 - 4 x ^{2}}{5}

\frac{( x + 9 ) ^{2}}{81} + \frac{( y - 1 ) ^{2}}{9} = 1

What is ((x^2)/(64))+((y^2)/(36))=1 ?
The solution to ((x^2)/(64))+((y^2)/(36))=1 is Ellipse with (h,k)=(0,0),a=8,b=6