What is (x^2)/(8^2)+(y^2)/(5^2)=1 ?

The solution to (x^2)/(8^2)+(y^2)/(5^2)=1 is Ellipse with (h,k)=(0,0),a=8,b=5

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(x^2)/(8^2)+(y^2)/(5^2)=1

\frac{x ^{2}}{8 ^{2}} + \frac{y ^{2}}{5 ^{2}} = 1

(h, k) = (0, 0), a = 8, b = 5

Solution steps

\frac{x ^{2}}{8 ^{2}} + \frac{y ^{2}}{5 ^{2}} = 1

Rewrite

\frac{x ^{2}}{8 ^{2}} + \frac{y ^{2}}{5 ^{2}} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{8 ^{2}} + \frac{( y - 0 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 8, b = 5

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 8, b = 5

x^{2} - 4 x + 4 y^{2} + 4 y + 1 = 0

25 x^{2} + 49 y^{2} = 49

x^{2} + x + 2 y^{2} + y - 1 = 0

\frac{( x - 4 ) ^{2}}{5} + \frac{( y - 6 ) ^{2}}{9} = 1

(\frac{( x + 2 ) ^{2}}{25}) + (\frac{( y - 1 ) ^{2}}{169}) = 1

What is (x^2)/(8^2)+(y^2)/(5^2)=1 ?
The solution to (x^2)/(8^2)+(y^2)/(5^2)=1 is Ellipse with (h,k)=(0,0),a=8,b=5