What is 2x^2-4x+y^2+2y-5=0 ?

The solution to 2x^2-4x+y^2+2y-5=0 is Ellipse with (h,k)=(1,-1),a=2,b=2sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2x^2-4x+y^2+2y-5=0

2 x^{2} - 4 x + y^{2} + 2 y - 5 = 0

(h, k) = (1, - 1), a = 2, b = 22

Solution steps

2 x^{2} - 4 x + y^{2} + 2 y - 5 = 0

Rewrite

2 x^{2} - 4 x + y^{2} + 2 y - 5 = 0

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{2 ^{2}} + \frac{( y - ( - 1 ) ) ^{2}}{( 2 2 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, - 1), a = 2, b = 22

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (1, - 1), b = 22, a = 2

4 x^{2} - 40 x + 9 y^{2} + 54 y + 145 = 0

9 X^{2} + Y^{2} = 81

\frac{( x ^{2} - 2 x + 1 )}{34} + \frac{( y ^{2} - 8 y + 16 )}{25} = 1

y^{2} \leq - 4 x^{2} + 4

\frac{( x - 4 ) ^{2}}{35} + \frac{( y - 2 ) ^{2}}{39} = 1

What is 2x^2-4x+y^2+2y-5=0 ?
The solution to 2x^2-4x+y^2+2y-5=0 is Ellipse with (h,k)=(1,-1),a=2,b=2sqrt(2)