What is ((y+7)^2)/(16)+((x-5)^2)/(25)=1 ?

The solution to ((y+7)^2)/(16)+((x-5)^2)/(25)=1 is Ellipse with (h,k)=(5,-7),a=5,b=4

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((y+7)^2)/(16)+((x-5)^2)/(25)=1

\frac{( y + 7 ) ^{2}}{16} + \frac{( x - 5 ) ^{2}}{25} = 1

(h, k) = (5, - 7), a = 5, b = 4

Solution steps

\frac{( y + 7 ) ^{2}}{16} + \frac{( x - 5 ) ^{2}}{25} = 1

Rewrite

\frac{( y + 7 ) ^{2}}{16} + \frac{( x - 5 ) ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - 5 ) ^{2}}{5 ^{2}} + \frac{( y - ( - 7 ) ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (5, - 7), a = 5, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (5, - 7), a = 5, b = 4

\frac{4}{x + y i} = x - y i

4 (x + 3)^{2} + y^{2} = 16

2 (1 + 2 y) (y - 2) = - (2 x - 3) (x - 7)

\frac{( x + 1 ) ^{2}}{25} + \frac{( y - 3 ) ^{2}}{36} = 1

\frac{( x + 4 ) ^{2}}{4} + \frac{( y + 2 ) ^{2}}{16} = 1

What is ((y+7)^2)/(16)+((x-5)^2)/(25)=1 ?
The solution to ((y+7)^2)/(16)+((x-5)^2)/(25)=1 is Ellipse with (h,k)=(5,-7),a=5,b=4