What is (12(x-1)^2)/(24)+(3y^2)/(24)= 24/24 ?

The solution to (12(x-1)^2)/(24)+(3y^2)/(24)= 24/24 is Ellipse with (h,k)=(1,0),a=sqrt(2),b=2sqrt(2)

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(12(x-1)^2)/(24)+(3y^2)/(24)= 24/24

\frac{12 ( x - 1 ) ^{2}}{24} + \frac{3 y ^{2}}{24} = \frac{24}{24}

(h, k) = (1, 0), a = 2, b = 22

Solution steps

\frac{12 ( x - 1 ) ^{2}}{24} + \frac{3 y ^{2}}{24} = \frac{24}{24}

Rewrite

\frac{12 ( x - 1 ) ^{2}}{24} + \frac{3 y ^{2}}{24} = \frac{24}{24}

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{( 2 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 2 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, 0), a = 2, b = 22

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (1, 0), b = 22, a = 2

10 x^{2} - 70 = - 7 y^{2}

2 x^{2} + 3 (y - 2)^{2} = 20

2 x^{2} + 8 x + y^{2} - 3 y = 0

\frac{x ^{2}}{179} + \frac{y ^{2}}{120} = 1

2 x^{2} + y^{2} = 57

What is (12(x-1)^2)/(24)+(3y^2)/(24)= 24/24 ?
The solution to (12(x-1)^2)/(24)+(3y^2)/(24)= 24/24 is Ellipse with (h,k)=(1,0),a=sqrt(2),b=2sqrt(2)