What is (x^2)/(25)+(y^2)/(6^2)=1 ?

The solution to (x^2)/(25)+(y^2)/(6^2)=1 is Ellipse with (h,k)=(0,0),a=5,b=6

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(x^2)/(25)+(y^2)/(6^2)=1

\frac{x ^{2}}{25} + \frac{y ^{2}}{6 ^{2}} = 1

(h, k) = (0, 0), a = 5, b = 6

Solution steps

\frac{x ^{2}}{25} + \frac{y ^{2}}{6 ^{2}} = 1

Rewrite

\frac{x ^{2}}{25} + \frac{y ^{2}}{6 ^{2}} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( y - 0 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 5, b = 6

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 6, a = 5

\frac{( X + 3 ) ^{2}}{49} + \frac{( Y + 2 ) ^{2}}{36} = 1

16 x^{2} + 25 y^{2} + 224 + 250 y - 191 = 0

\frac{( x + 3 ) ^{2}}{16} + \frac{( y + 2 ) ^{2}}{9} = 1

9 y^{2} + 36 y + 4 x^{2} = 0

16 x^{(2)} + 25 y^{(2)} - 128 x + 100 y = 0

What is (x^2)/(25)+(y^2)/(6^2)=1 ?
The solution to (x^2)/(25)+(y^2)/(6^2)=1 is Ellipse with (h,k)=(0,0),a=5,b=6