What is (((x+5)^2)}{36}+\frac{((y-1)^2))/9 =1 ?

The solution to (((x+5)^2)}{36}+\frac{((y-1)^2))/9 =1 is Ellipse with (h,k)=(-5,1),a=6,b=3

Popular >

(((x+5)^2)}{36}+\frac{((y-1)^2))/9 =1

\frac{( ( x + 5 ) ^{2} )}{36} + \frac{( ( y - 1 ) ^{2} )}{9} = 1

(h, k) = (- 5, 1), a = 6, b = 3

Solution steps

\frac{( x + 5 ) ^{2}}{36} + \frac{( y - 1 ) ^{2}}{9} = 1

Rewrite

\frac{( x + 5 ) ^{2}}{36} + \frac{( y - 1 ) ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 5 ) ) ^{2}}{6 ^{2}} + \frac{( y - 1 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 5, 1), a = 6, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 5, 1), a = 6, b = 3

x^{2} + y^{2} = 25 y

\frac{\frac{3 x ^{2}}{4}}{12} + (\frac{\frac{4 y}{4}}{12})^{2} = 1

\frac{( X + 7 ) ^{2}}{16} + \frac{( Y - 5 ) ^{2}}{25} = 1

\frac{y}{( \frac{x}{5} ) ^{2} + ( \frac{y}{2} ) ^{2}} = 1

(\frac{X - 2}{2})^{2} + (\frac{Y + 3}{4})^{2} = 1

What is (((x+5)^2)}{36}+\frac{((y-1)^2))/9 =1 ?
The solution to (((x+5)^2)}{36}+\frac{((y-1)^2))/9 =1 is Ellipse with (h,k)=(-5,1),a=6,b=3