What is (3x-2)^2=84y-112 ?

The solution to (3x-2)^2=84y-112 is Parabola with (h,k)=(2/3 , 4/3),p= 7/3

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(3x-2)^2=84y-112

(3 x - 2)^{2} = 84 y - 112

(h, k) = (\frac{2}{3}, \frac{4}{3}), p = \frac{7}{3}

Solution steps

(3 x - 2)^{2} = 84 y - 112

Rewrite

(3 x - 2)^{2} = 84 y - 112

in the standard form:

4 \cdot \frac{7}{3} (y - \frac{4}{3}) = (x - \frac{2}{3})^{2}

Therefore parabola properties are:

(h, k) = (\frac{2}{3}, \frac{4}{3}), p = \frac{7}{3}

y^{2} = x - 4

(y - 3)^{2} = 20 x

3 x^{2} + 4 x - 2 y = - 2

y < x^{2} + 3

3 x^{2} + 6 x + 6 y = - 27

What is (3x-2)^2=84y-112 ?
The solution to (3x-2)^2=84y-112 is Parabola with (h,k)=(2/3 , 4/3),p= 7/3