What is x^2+8y^2=64 ?

The solution to x^2+8y^2=64 is Ellipse with (h,k)=(0,0),a=8,b=2sqrt(2)

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x^2+8y^2=64

x^{2} + 8 y^{2} = 64

(h, k) = (0, 0), a = 8, b = 22

Solution steps

x^{2} + 8 y^{2} = 64

Rewrite

x^{2} + 8 y^{2} = 64

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{8 ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 2 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 8, b = 22

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 8, b = 22

16 x^{2} + 4 y^{2} + 96 x - 16 y + 96 = 0

\frac{( x + 1 ) ^{2}}{49} + \frac{( y - 7 ) ^{2}}{1} = 1

4 (x - 3)^{2} + 2 (y + 4)^{2} = 16

3 x^{2} - 12 x + y^{2} - 4 y + 1 = 0

(\frac{u + v}{u ^{2} + v ^{2}}) + (\frac{- v + u}{u ^{2} + v ^{2}}) = 1

What is x^2+8y^2=64 ?
The solution to x^2+8y^2=64 is Ellipse with (h,k)=(0,0),a=8,b=2sqrt(2)