What is ((x-2)^2)/(3.5^2)+((y-1)^2)/(2.5^2)=1 ?

The solution to ((x-2)^2)/(3.5^2)+((y-1)^2)/(2.5^2)=1 is Ellipse with (h,k)=(2,1),a=3.5,b=2.5

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((x-2)^2)/(3.5^2)+((y-1)^2)/(2.5^2)=1

\frac{( x - 2 ) ^{2}}{3. 5 ^{2}} + \frac{( y - 1 ) ^{2}}{2. 5 ^{2}} = 1

(h, k) = (2, 1), a = 3.5, b = 2.5

Solution steps

\frac{( x - 2 ) ^{2}}{3. 5 ^{2}} + \frac{( y - 1 ) ^{2}}{2. 5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, 1), a = 3.5, b = 2.5

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (2, 1), a = 3.5, b = 2.5

(3 p + 2 q) 2 = 9 p^{2} + 4 q^{2}

\frac{( x + 2 ) ^{2}}{16} + \frac{( y - 2 ) ^{2}}{36} = 1

\frac{( x + 3 ) ^{2}}{16} + \frac{( y - 4 ) ^{2}}{9} = 1

\frac{( x - 5 ) ^{2}}{9} + \frac{( y - 4 ) ^{2}}{36} = 1

\frac{x ^{2}}{4} + \frac{y ^{2}}{20} = 1

What is ((x-2)^2)/(3.5^2)+((y-1)^2)/(2.5^2)=1 ?
The solution to ((x-2)^2)/(3.5^2)+((y-1)^2)/(2.5^2)=1 is Ellipse with (h,k)=(2,1),a=3.5,b=2.5