What is ((x^2)}{16}+\frac{(y^2))/9 =1 ?

The solution to ((x^2)}{16}+\frac{(y^2))/9 =1 is Ellipse with (h,k)=(0,0),a=4,b=3

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((x^2)}{16}+\frac{(y^2))/9 =1

\frac{( x ^{2} )}{16} + \frac{( y ^{2} )}{9} = 1

(h, k) = (0, 0), a = 4, b = 3

Solution steps

\frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

Rewrite

\frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 4, b = 3

- 1 = x^{2} + y^{2}

\frac{x ^{2}}{9} + \frac{y ^{2}}{20} = 1

\frac{x ^{2} + y ^{2} + 8 y - 16}{x ^{2} + y ^{2} + 8 y + 16} = 9

5 x^{2} - 30 x + 9 y^{2} - 3 y + 36 = 0

2 x^{2} - 9 x + 4 y^{2} + 8 x = 16

What is ((x^2)}{16}+\frac{(y^2))/9 =1 ?
The solution to ((x^2)}{16}+\frac{(y^2))/9 =1 is Ellipse with (h,k)=(0,0),a=4,b=3