What is ((x)^2)/(49)+((y)^2)/(25)=1 ?

The solution to ((x)^2)/(49)+((y)^2)/(25)=1 is Ellipse with (h,k)=(0,0),a=7,b=5

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((x)^2)/(49)+((y)^2)/(25)=1

\frac{( x ) ^{2}}{49} + \frac{( y ) ^{2}}{25} = 1

(h, k) = (0, 0), a = 7, b = 5

Solution steps

\frac{x ^{2}}{49} + \frac{y ^{2}}{25} = 1

Rewrite

\frac{x ^{2}}{49} + \frac{y ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{7 ^{2}} + \frac{( y - 0 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 7, b = 5

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 7, b = 5

\frac{( - y )}{- 2 - x} = \frac{( - 1 )}{\frac{( 4 - y )}{6 - x}}

9 (x + 9)^{2} + 4 (y - 12)^{2} = 1284

(x - 4)^{2} + y^{2} = \frac{1}{4} ((x + 2)^{2} + (y - y))

\frac{( x - 2 ) ^{2}}{9} + \frac{( y + 2 ) ^{2}}{25} = 1

x^{2} + 4 y^{2} + 10 x + 8 y - 13 = 0

What is ((x)^2)/(49)+((y)^2)/(25)=1 ?
The solution to ((x)^2)/(49)+((y)^2)/(25)=1 is Ellipse with (h,k)=(0,0),a=7,b=5