What is ((x+1)^2)/(21)+((y+5)^2)/(25)=1 ?

The solution to ((x+1)^2)/(21)+((y+5)^2)/(25)=1 is Ellipse with (h,k)=(-1,-5),a=sqrt(21),b=5

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((x+1)^2)/(21)+((y+5)^2)/(25)=1

\frac{( x + 1 ) ^{2}}{21} + \frac{( y + 5 ) ^{2}}{25} = 1

(h, k) = (- 1, - 5), a = 21, b = 5

Solution steps

\frac{( x + 1 ) ^{2}}{21} + \frac{( y + 5 ) ^{2}}{25} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{21} + \frac{( y + 5 ) ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{( 21 ) ^{2}} + \frac{( y - ( - 5 ) ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, - 5), a = 21, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 1, - 5), b = 5, a = 21

4 x^{2} + 3 y^{2} = 7

25 x^{2} + 4 y^{2} - 250 x - 16 y = - 541

x^{2} + \frac{z ^{2}}{225} = 1

4 x^{2} + 12 y^{2} - 4 x - 24 y + 1 = 0

\frac{x ^{2}}{4} + x + 9 y^{2} + 18 y + \frac{31}{4} = 0

What is ((x+1)^2)/(21)+((y+5)^2)/(25)=1 ?
The solution to ((x+1)^2)/(21)+((y+5)^2)/(25)=1 is Ellipse with (h,k)=(-1,-5),a=sqrt(21),b=5