What is ((x+4)^2)/(6^2)+((y+6)^2)/(7^2)=1 ?

The solution to ((x+4)^2)/(6^2)+((y+6)^2)/(7^2)=1 is Ellipse with (h,k)=(-4,-6),a=6,b=7

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((x+4)^2)/(6^2)+((y+6)^2)/(7^2)=1

\frac{( x + 4 ) ^{2}}{6 ^{2}} + \frac{( y + 6 ) ^{2}}{7 ^{2}} = 1

(h, k) = (- 4, - 6), a = 6, b = 7

Solution steps

\frac{( x + 4 ) ^{2}}{6 ^{2}} + \frac{( y + 6 ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 4, - 6), a = 6, b = 7

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 4, - 6), b = 7, a = 6

X^{2} + 4 Y^{2} - 6 X - 16 Y + 21 = 0

(5 p + 3 q) 2 = 25 p^{2} + 9 q^{2}

25 x^{2} + 9 y^{2} + 100 x + 36 y - 89 = 0

\frac{x ^{2}}{4} + (1 - \frac{y}{2})^{2} = 1

\frac{( x - 12 ) ^{2}}{100} + \frac{( y + 7 ) ^{2}}{36} = 1

What is ((x+4)^2)/(6^2)+((y+6)^2)/(7^2)=1 ?
The solution to ((x+4)^2)/(6^2)+((y+6)^2)/(7^2)=1 is Ellipse with (h,k)=(-4,-6),a=6,b=7