What is -8y^2+72=9x^2 ?

The solution to -8y^2+72=9x^2 is Ellipse with (h,k)=(0,0),a=2sqrt(2),b=3

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-8y^2+72=9x^2

- 8 y^{2} + 72 = 9 x^{2}

(h, k) = (0, 0), a = 22, b = 3

Solution steps

- 8 y^{2} + 72 = 9 x^{2}

Rewrite

- 8 y^{2} + 72 = 9 x^{2}

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 2 2 ) ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 22, b = 3

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 3, a = 22

\frac{( x + 3 ) ^{2}}{36} + \frac{( y - 4 ) ^{2}}{16} = 1

2 (x - 1)^{2} + 3 (y - 2)^{2} = 6

10 - \frac{x ^{2}}{2} - y^{2} = x^{2} + 4 y^{2}

x^{2} + 1 - 2 x + 4 y^{2} + 16 y > 0

(x + 5)^{2} + 9 (y + 3)^{2} = 36

What is -8y^2+72=9x^2 ?
The solution to -8y^2+72=9x^2 is Ellipse with (h,k)=(0,0),a=2sqrt(2),b=3