What is ((x+5)^2)/4+((y+5)^2)/(25)=1 ?

The solution to ((x+5)^2)/4+((y+5)^2)/(25)=1 is Ellipse with (h,k)=(-5,-5),a=2,b=5

Popular >

((x+5)^2)/4+((y+5)^2)/(25)=1

\frac{( x + 5 ) ^{2}}{4} + \frac{( y + 5 ) ^{2}}{25} = 1

(h, k) = (- 5, - 5), a = 2, b = 5

Solution steps

\frac{( x + 5 ) ^{2}}{4} + \frac{( y + 5 ) ^{2}}{25} = 1

Rewrite

\frac{( x + 5 ) ^{2}}{4} + \frac{( y + 5 ) ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 5 ) ) ^{2}}{2 ^{2}} + \frac{( y - ( - 5 ) ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 5, - 5), a = 2, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 5, - 5), b = 5, a = 2

x^{2} + 4 y^{2} = 15

2 x^{2} + y^{2} - 8 y - 2 x + 1 = 0

8 x^{2} + 12 y^{2} = 96

\frac{x ^{2}}{9} + \frac{y ^{2}}{4} = \frac{x}{6} + \frac{y}{3}

\frac{( x + 1 ) ^{2}}{36} + \frac{( y + 2 ) ^{2}}{9} = 1

What is ((x+5)^2)/4+((y+5)^2)/(25)=1 ?
The solution to ((x+5)^2)/4+((y+5)^2)/(25)=1 is Ellipse with (h,k)=(-5,-5),a=2,b=5