What is 12x^2+8y^2=96 ?

The solution to 12x^2+8y^2=96 is Ellipse with (h,k)=(0,0),a=2sqrt(2),b=2sqrt(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

12x^2+8y^2=96

12 x^{2} + 8 y^{2} = 96

(h, k) = (0, 0), a = 22, b = 23

Solution steps

12 x^{2} + 8 y^{2} = 96

Rewrite

12 x^{2} + 8 y^{2} = 96

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 2 2 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 3 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 22, b = 23

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 23, a = 22

10 x^{2} + 3 y^{2} = 30

\frac{x ^{2}}{k} + \frac{y ^{2}}{4 + k} = 1

\frac{( x + 1 ) ^{2}}{64} + \frac{( y - 5 ) ^{2}}{9} = 1

\frac{( ( x - 4 ) ^{2} )}{36} + \frac{( ( y - 2 ) ^{2} )}{9} = 1

9 x^{2} + 16 y^{2} - 90 x - 160 y + 481 = 0

What is 12x^2+8y^2=96 ?
The solution to 12x^2+8y^2=96 is Ellipse with (h,k)=(0,0),a=2sqrt(2),b=2sqrt(3)