What is ((x-23)^2)/(841)+((y+28)^2)/(484)=1 ?

The solution to ((x-23)^2)/(841)+((y+28)^2)/(484)=1 is Ellipse with (h,k)=(23,-28),a=29,b=22

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((x-23)^2)/(841)+((y+28)^2)/(484)=1

\frac{( x - 23 ) ^{2}}{841} + \frac{( y + 28 ) ^{2}}{484} = 1

(h, k) = (23, - 28), a = 29, b = 22

Solution steps

\frac{( x - 23 ) ^{2}}{841} + \frac{( y + 28 ) ^{2}}{484} = 1

Rewrite

\frac{( x - 23 ) ^{2}}{841} + \frac{( y + 28 ) ^{2}}{484} = 1

in the form of the standard ellipse equation

\frac{( x - 23 ) ^{2}}{2 9 ^{2}} + \frac{( y - ( - 28 ) ) ^{2}}{2 2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (23, - 28), a = 29, b = 22

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (23, - 28), a = 29, b = 22

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\frac{x ^{2}}{25} + \frac{y ^{2}}{b ^{2}} = 1

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What is ((x-23)^2)/(841)+((y+28)^2)/(484)=1 ?
The solution to ((x-23)^2)/(841)+((y+28)^2)/(484)=1 is Ellipse with (h,k)=(23,-28),a=29,b=22