What is (x^2)/(49)+(y^2)/(40)=1 ?

The solution to (x^2)/(49)+(y^2)/(40)=1 is Ellipse with (h,k)=(0,0),a=7,b=2sqrt(10)

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(x^2)/(49)+(y^2)/(40)=1

\frac{x ^{2}}{49} + \frac{y ^{2}}{40} = 1

(h, k) = (0, 0), a = 7, b = 210

Solution steps

\frac{x ^{2}}{49} + \frac{y ^{2}}{40} = 1

Rewrite

\frac{x ^{2}}{49} + \frac{y ^{2}}{40} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{7 ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 10 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 7, b = 210

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 7, b = 210

3 = \frac{x ^{2}}{4} + \frac{y ^{2}}{9}

\frac{( x - 3 ) ^{2}}{49} + \frac{( y - 5 ) ^{2}}{16} = 1

\frac{x ^{2}}{64} + \frac{( y - 3 ) ^{2}}{9} = 1

4 x^{2} + z^{2} = 16

\frac{( x - 5 ) ^{2}}{9} + \frac{( y - 2 ) ^{2}}{36} = 1

What is (x^2)/(49)+(y^2)/(40)=1 ?
The solution to (x^2)/(49)+(y^2)/(40)=1 is Ellipse with (h,k)=(0,0),a=7,b=2sqrt(10)