What is ((x^{(2)}))/((36))+((y^{(2)}))/((16))=1 ?

The solution to ((x^{(2)}))/((36))+((y^{(2)}))/((16))=1 is Ellipse with (h,k)=(0,0),a=6,b=4

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((x^{(2)}))/((36))+((y^{(2)}))/((16))=1

\frac{( x ^{(2)} )}{( 36 )} + \frac{( y ^{(2)} )}{( 16 )} = 1

(h, k) = (0, 0), a = 6, b = 4

Solution steps

\frac{x ^{2}}{36} + \frac{y ^{2}}{16} = 1

Rewrite

\frac{x ^{2}}{36} + \frac{y ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{6 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 6, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 6, b = 4

16 x^{2} + 36 y^{2} - 256 x + 576 y + 2752 = 0

16 x^{2} + 4 y^{2} + 32 x + 32 y + 16 = 0

x^{2} + 5 y^{2} = 150

36 x^{2} + 16 y^{2} = 49

81 X^{2} + 49 Y^{2} = 3969

What is ((x^{(2)}))/((36))+((y^{(2)}))/((16))=1 ?
The solution to ((x^{(2)}))/((36))+((y^{(2)}))/((16))=1 is Ellipse with (h,k)=(0,0),a=6,b=4