What is (p(x))/(3x-2(x+2)+5(x+3))=3(x+4) ?

The solution to (p(x))/(3x-2(x+2)+5(x+3))=3(x+4) is Parabola with (h,k)=(-35/12 ,-169/8),p= 1/72

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(p(x))/(3x-2(x+2)+5(x+3))=3(x+4)

\frac{p ( x )}{3 x - 2 ( x + 2 ) + 5 ( x + 3 )} = 3 (x + 4)

(h, k) = (- \frac{35}{12}, - \frac{169}{8}), p = \frac{1}{72}

Solution steps

\frac{y}{3 x - 2 ( x + 2 ) + 5 ( x + 3 )} = 3 (x + 4)

Rewrite

\frac{y}{3 x - 2 ( x + 2 ) + 5 ( x + 3 )} - 3 (x + 4) = 0

in the standard form

4 \cdot \frac{1}{72} (y - (- \frac{169}{8})) = (x - (- \frac{35}{12}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{35}{12}, - \frac{169}{8}), p = \frac{1}{72}

(x - 1) + 4 (y - 2)^{2} = 10

x + (y - 6)^{2} = 0

(y + 2)^{2} = - 2 (x - 3)

(y + 3)^{2} = 6 (x + 12)

5 (y + 1) 3 + x^{2} = 1

What is (p(x))/(3x-2(x+2)+5(x+3))=3(x+4) ?
The solution to (p(x))/(3x-2(x+2)+5(x+3))=3(x+4) is Parabola with (h,k)=(-35/12 ,-169/8),p= 1/72