What is (((x+1)^2))/9+(((y+1)^2))/(16)=1 ?

The solution to (((x+1)^2))/9+(((y+1)^2))/(16)=1 is Ellipse with (h,k)=(-1,-1),a=3,b=4

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(((x+1)^2))/9+(((y+1)^2))/(16)=1

\frac{( ( x + 1 ) ^{2} )}{9} + \frac{( ( y + 1 ) ^{2} )}{16} = 1

(h, k) = (- 1, - 1), a = 3, b = 4

Solution steps

\frac{( x + 1 ) ^{2}}{9} + \frac{( y + 1 ) ^{2}}{16} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{9} + \frac{( y + 1 ) ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{3 ^{2}} + \frac{( y - ( - 1 ) ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, - 1), a = 3, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 1, - 1), b = 4, a = 3

55 x^{2} + 5 y^{2} = 4

81 (x - 2)^{2} + 36 (y - 3)^{2} = 2916

3 x^{2} + 5 y^{2} - 6 x - 20 y + 8 = 0

\frac{( x + \frac{17}{2} ) ^{2}}{144} + \frac{( y + \frac{13}{2} ) ^{2}}{121} = 1

\frac{x ^{2}}{3} + \frac{y ^{2}}{5} = 1

What is (((x+1)^2))/9+(((y+1)^2))/(16)=1 ?
The solution to (((x+1)^2))/9+(((y+1)^2))/(16)=1 is Ellipse with (h,k)=(-1,-1),a=3,b=4