What is ((x+2)^2)/(15)+(y^2)/(64)=1 ?

The solution to ((x+2)^2)/(15)+(y^2)/(64)=1 is Ellipse with (h,k)=(-2,0),a=sqrt(15),b=8

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((x+2)^2)/(15)+(y^2)/(64)=1

\frac{( x + 2 ) ^{2}}{15} + \frac{y ^{2}}{64} = 1

(h, k) = (- 2, 0), a = 15, b = 8

Solution steps

\frac{( x + 2 ) ^{2}}{15} + \frac{y ^{2}}{64} = 1

Rewrite

\frac{( x + 2 ) ^{2}}{15} + \frac{y ^{2}}{64} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 2 ) ) ^{2}}{( 15 ) ^{2}} + \frac{( y - 0 ) ^{2}}{8 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 2, 0), a = 15, b = 8

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 2, 0), b = 8, a = 15

(x^{2} + 8 x) + (3 y^{2} + 8 y) = 11

\frac{( x + 2 ) ^{2}}{20} + \frac{( y - 3 ) ^{2}}{4} = 1

- 4 x^{2} - 9 y^{2} + 8 x - 18 y + 23 = 0

\frac{16 x ^{2}}{144} + \frac{9 y ^{2}}{144} = 1

x^{2} + 3 y^{2} - 13 - y^{2} - 4 x = 0

What is ((x+2)^2)/(15)+(y^2)/(64)=1 ?
The solution to ((x+2)^2)/(15)+(y^2)/(64)=1 is Ellipse with (h,k)=(-2,0),a=sqrt(15),b=8