What is ((x-2)^2)/9+((y-2)^2)/(36)=1 ?

The solution to ((x-2)^2)/9+((y-2)^2)/(36)=1 is Ellipse with (h,k)=(2,2),a=3,b=6

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((x-2)^2)/9+((y-2)^2)/(36)=1

\frac{( x - 2 ) ^{2}}{9} + \frac{( y - 2 ) ^{2}}{36} = 1

(h, k) = (2, 2), a = 3, b = 6

Solution steps

\frac{( x - 2 ) ^{2}}{9} + \frac{( y - 2 ) ^{2}}{36} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{9} + \frac{( y - 2 ) ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{3 ^{2}} + \frac{( y - 2 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, 2), a = 3, b = 6

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (2, 2), b = 6, a = 3

\frac{( x + 4 ) ^{2}}{0.25} + \frac{( y - 8 ) ^{2}}{1} = 1

3 x^{2} + z^{2} = 8 - x^{2} - z^{2}

- \frac{x ^{2}}{1} - \frac{y ^{2}}{4} = 1

\frac{( x + 2 ) ^{2}}{25} + \frac{( y - 3 ) ^{2}}{4} = 1

\frac{x ^{2}}{14} + \frac{y ^{2}}{6} = 1

What is ((x-2)^2)/9+((y-2)^2)/(36)=1 ?
The solution to ((x-2)^2)/9+((y-2)^2)/(36)=1 is Ellipse with (h,k)=(2,2),a=3,b=6