What is (((x-2)^2}{16})+(\frac{y^2)/9)=1 ?

The solution to (((x-2)^2}{16})+(\frac{y^2)/9)=1 is Ellipse with (h,k)=(2,0),a=4,b=3

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(((x-2)^2}{16})+(\frac{y^2)/9)=1

(\frac{( x - 2 ) ^{2}}{16}) + (\frac{y ^{2}}{9}) = 1

(h, k) = (2, 0), a = 4, b = 3

Solution steps

\frac{( x - 2 ) ^{2}}{16} + \frac{y ^{2}}{9} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{16} + \frac{y ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, 0), a = 4, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (2, 0), a = 4, b = 3

\frac{x}{x ^{2} + y ^{2}} = \frac{3}{2}

4 x^{2} + 25 y^{2} - 50 y - 75 = 0

x^{2} + 4 y^{2} - 2.71 = 0

\frac{( x - 5 ) ^{2}}{144} + \frac{( y + 2 ) ^{2}}{169} = 1

4 y^{(2)} + 2 x^{(2)} - 4 y - 8 x - 15 = 0

What is (((x-2)^2}{16})+(\frac{y^2)/9)=1 ?
The solution to (((x-2)^2}{16})+(\frac{y^2)/9)=1 is Ellipse with (h,k)=(2,0),a=4,b=3