What is ((x-0)^2)/(2^2)+((y-(-3))^2)/(4^2)=1 ?

The solution to ((x-0)^2)/(2^2)+((y-(-3))^2)/(4^2)=1 is Ellipse with (h,k)=(0,-3),a=2,b=4

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((x-0)^2)/(2^2)+((y-(-3))^2)/(4^2)=1

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - ( - 3 ) ) ^{2}}{4 ^{2}} = 1

(h, k) = (0, - 3), a = 2, b = 4

Solution steps

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - ( - 3 ) ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, - 3), a = 2, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, - 3), b = 4, a = 2

x^{2} + \frac{( y - 1 ) ^{2}}{4} = 1

1 x^{2} + 3 y^{2} + 8 x + 9 y - 14 = 0

\frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 3

2 x^{2} + y^{2} + x + y = 0

9 x^{2} + 18 x + 25 y^{2} - 100 y = 116

What is ((x-0)^2)/(2^2)+((y-(-3))^2)/(4^2)=1 ?
The solution to ((x-0)^2)/(2^2)+((y-(-3))^2)/(4^2)=1 is Ellipse with (h,k)=(0,-3),a=2,b=4