What is the radius x^2+y^2-18x-14y+124=0 ?

The radius x^2+y^2-18x-14y+124=0 is r=sqrt(6)

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radius x^2+y^2-18x-14y+124=0

radius

x^{2} + y^{2} - 18 x - 14 y + 124 = 0

r = 6

Solution steps

x^{2} + y^{2} - 18 x - 14 y + 124 = 0

Rewrite

x^{2} + y^{2} - 18 x - 14 y + 124 = 0

in the form of the standard circle equation

(x - 9)^{2} + (y - 7)^{2} = (6)^{2}

Therefore the circle properties are:

(a, b) = (9, 7), r = 6

And the radius is:

r = 6

\frac{x ^{2}}{9} + \frac{y ^{2}}{25} = 1

9 (x - 1)^{2} - 16 (y + 2)^{2} = 144

9 x^{2} + 4 y^{2} + 36 x - 24 y + 36 = 0

f (x) = 3 x^{2} - 18 x + 23

x^{2} + y^{2} \leq 25

What is the radius x^2+y^2-18x-14y+124=0 ?
The radius x^2+y^2-18x-14y+124=0 is r=sqrt(6)