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Popular >

α^2+2β^2=1

Solution

α^{2} + 2 β^{2} = 1

Solution

(h, k) = (0, 0), a = 1, b = \frac{1}{2}

Solution steps

α^{2} + 2 β^{2} = 1

Rewrite

α^{2} + 2 β^{2} = 1

in the form of the standard ellipse equation

\frac{( α - 0 ) ^{2}}{1 ^{2}} + \frac{( β - 0 ) ^{2}}{( \frac{1}{2} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 1, b = \frac{1}{2}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 1, b = \frac{1}{2}

Popular Examples

8(x+6/7)^2+3(y-3/2)^2=27

8 (x + \frac{6}{7})^{2} + 3 (y - \frac{3}{2})^{2} = 27

((y-2)^2)/4+((z-3)^2)/1 =1

\frac{( y - 2 ) ^{2}}{4} + \frac{( z - 3 ) ^{2}}{1} = 1

(x^2)/(-12)+(y^2)/(-12-16)=1

\frac{x ^{2}}{- 12} + \frac{y ^{2}}{- 12 - 16} = 1

((X+2)^2)/9+((Y-1)^2)/(16)=1

\frac{( X + 2 ) ^{2}}{9} + \frac{( Y - 1 ) ^{2}}{16} = 1

x/(x^2+y^2)<= 1/2

\frac{x}{x ^{2} + y ^{2}} \leq \frac{1}{2}

Frequently Asked Questions (FAQ)

What is α^2+2β^2=1 ?
The solution to α^2+2β^2=1 is Ellipse with (h,k)=(0,0),a=1,b=sqrt(1/2)