What is 16x^2+7y^2=112 ?

The solution to 16x^2+7y^2=112 is Ellipse with (h,k)=(0,0),a=sqrt(7),b=4

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16x^2+7y^2=112

16 x^{2} + 7 y^{2} = 112

(h, k) = (0, 0), a = 7, b = 4

Solution steps

16 x^{2} + 7 y^{2} = 112

Rewrite

16 x^{2} + 7 y^{2} = 112

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 7 ) ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 7, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 4, a = 7

\frac{( x + 1 ) ^{2}}{2} + \frac{y ^{2}}{8} = 1

y^{2} = - 0.25 x^{2} + 1

x, \frac{x ^{2}}{25} + \frac{Y ( x ) ^{2}}{4} = 1

\frac{( x - 4 ) ^{2}}{16} + \frac{( y + 3 ) ^{2}}{25} = 1

\frac{( x + 6.5 ) ^{2}}{56.25} + \frac{( y - 3 ) ^{2}}{36} = 1

What is 16x^2+7y^2=112 ?
The solution to 16x^2+7y^2=112 is Ellipse with (h,k)=(0,0),a=sqrt(7),b=4