What is 4x^2+8y^2=16 ?

The solution to 4x^2+8y^2=16 is Ellipse with (h,k)=(0,0),a=2,b=sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4x^2+8y^2=16

4 x^{2} + 8 y^{2} = 16

(h, k) = (0, 0), a = 2, b = 2

Solution steps

4 x^{2} + 8 y^{2} = 16

Rewrite

4 x^{2} + 8 y^{2} = 16

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 2, b = 2

x^{2} + 4 y^{2} - 6 x - 32 y + 72 = 0

(- y^{2}) = x^{2} + 12

\frac{( x - 3 ) ^{2}}{9} + \frac{( y + 1 ) ^{2}}{16} = 1

\frac{x ^{2}}{580 0 ^{2}} + \frac{y ^{2}}{150 0 ^{2}} = 1

9 x^{2} + y^{2} - 54 x - 6 y + 81 = 0

What is 4x^2+8y^2=16 ?
The solution to 4x^2+8y^2=16 is Ellipse with (h,k)=(0,0),a=2,b=sqrt(2)