What is x^2+(y^2)/(49)=1 ?

The solution to x^2+(y^2)/(49)=1 is Ellipse with (h,k)=(0,0),a=1,b=7

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x^2+(y^2)/(49)=1

x^{2} + \frac{y ^{2}}{49} = 1

(h, k) = (0, 0), a = 1, b = 7

Solution steps

x^{2} + \frac{y ^{2}}{49} = 1

Rewrite

x^{2} + \frac{y ^{2}}{49} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 1, b = 7

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 7, a = 1

\frac{( x + 2 ) ^{2}}{49} + \frac{( y - 3 ) ^{2}}{4} = 1

x^{2} + 4 y^{2} - 6 x + 12 y - 11 = 0

\frac{( x ^{2} )}{( 16 )} + \frac{( y ^{2} )}{( 25 )} = 1

- y = x^{2} + y^{2}

\frac{( x - 7 ) ^{2}}{81} + \frac{( y ) ^{2}}{9} = 1

What is x^2+(y^2)/(49)=1 ?
The solution to x^2+(y^2)/(49)=1 is Ellipse with (h,k)=(0,0),a=1,b=7