What is ((x-4)^2)/9+((y-7)^2)/(36)=1 ?

The solution to ((x-4)^2)/9+((y-7)^2)/(36)=1 is Ellipse with (h,k)=(4,7),a=3,b=6

Popular >

((x-4)^2)/9+((y-7)^2)/(36)=1

\frac{( x - 4 ) ^{2}}{9} + \frac{( y - 7 ) ^{2}}{36} = 1

(h, k) = (4, 7), a = 3, b = 6

Solution steps

\frac{( x - 4 ) ^{2}}{9} + \frac{( y - 7 ) ^{2}}{36} = 1

Rewrite

\frac{( x - 4 ) ^{2}}{9} + \frac{( y - 7 ) ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - 4 ) ^{2}}{3 ^{2}} + \frac{( y - 7 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (4, 7), a = 3, b = 6

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (4, 7), b = 6, a = 3

\frac{( ( x - 2 ) ^{2} )}{( 9 )} + \frac{( ( y + 5 ) ^{2} )}{( 25 )} = 1

16 x^{2} + 25 y^{2} = 1400

5 x^{2} + 9 y^{2} - 80 x + 54 y + 221 = 0

(\frac{x}{16})^{2} + \frac{y ^{2}}{81} = 1

11 x^{2} + 5 y^{2} + 110 x - 20 y + 240 = 0

What is ((x-4)^2)/9+((y-7)^2)/(36)=1 ?
The solution to ((x-4)^2)/9+((y-7)^2)/(36)=1 is Ellipse with (h,k)=(4,7),a=3,b=6