What is 49x^2+25y^2-1225=0 ?

The solution to 49x^2+25y^2-1225=0 is Ellipse with (h,k)=(0,0),a=5,b=7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

49x^2+25y^2-1225=0

49 x^{2} + 25 y^{2} - 1225 = 0

(h, k) = (0, 0), a = 5, b = 7

Solution steps

49 x^{2} + 25 y^{2} - 1225 = 0

Rewrite

49 x^{2} + 25 y^{2} - 1225 = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( y - 0 ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 5, b = 7

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 7, a = 5

15 x^{2} + 12 y^{2} + 30 x - 24 y = 150

2 x^{2} + 5 y^{2} - 4 x + y - 6 = 0

\frac{( x - 2.63 ) ^{2}}{1.34} + \frac{y ^{2}}{3.22} - 1 = 1

4 x^{2} + y^{2} - 32 x - 80 = 0

2 x^{2} + x + y^{2} - 6 = 0

What is 49x^2+25y^2-1225=0 ?
The solution to 49x^2+25y^2-1225=0 is Ellipse with (h,k)=(0,0),a=5,b=7