What is (x^2)/(3^2)+(y^2)/(7^2)=1 ?

The solution to (x^2)/(3^2)+(y^2)/(7^2)=1 is Ellipse with (h,k)=(0,0),a=3,b=7

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(x^2)/(3^2)+(y^2)/(7^2)=1

\frac{x ^{2}}{3 ^{2}} + \frac{y ^{2}}{7 ^{2}} = 1

(h, k) = (0, 0), a = 3, b = 7

Solution steps

\frac{x ^{2}}{3 ^{2}} + \frac{y ^{2}}{7 ^{2}} = 1

Rewrite

\frac{x ^{2}}{3 ^{2}} + \frac{y ^{2}}{7 ^{2}} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} + \frac{( y - 0 ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 3, b = 7

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 7, a = 3

- y^{2} - z^{2} = 1

\frac{( x - 5 ) ^{2}}{4} + \frac{( y + 2 ) ^{2}}{2} = 1

6 x^{2} + 144 y^{2} = 864

\frac{( x - ( - 1 ) ) ^{2}}{4 ^{2}} + \frac{( y - ( - 1 ) ) ^{2}}{3 ^{2}} = 1

81 x^{2} + 9 y^{2} = 64

What is (x^2)/(3^2)+(y^2)/(7^2)=1 ?
The solution to (x^2)/(3^2)+(y^2)/(7^2)=1 is Ellipse with (h,k)=(0,0),a=3,b=7