What is the vertices (x^2)/(64)+(y^2)/(100)=1 ?

The vertices (x^2)/(64)+(y^2)/(100)=1 is (0,10),(0,-10)

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vertices (x^2)/(64)+(y^2)/(100)=1

vertices

\frac{x ^{2}}{64} + \frac{y ^{2}}{100} = 1

(0, 10), (0, - 10)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

\frac{x ^{2}}{64} + \frac{y ^{2}}{100} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 10, a = 8

(0, 0 + 10), (0, 0 - 10)

Refine

(0, 10), (0, - 10)

\frac{x ^{2}}{16} + \frac{y ^{2}}{12} = 1

41 x^{2} + 16 y^{2} + 246 x - 192 y + 289 = 0

4 x^{2} + y^{2} - 8 x + 4 y - 8 = 0

\frac{x ^{2}}{4} + \frac{y ^{2}}{25} = 1

x^{2} + y^{2} - 4 y = 0

What is the vertices (x^2)/(64)+(y^2)/(100)=1 ?
The vertices (x^2)/(64)+(y^2)/(100)=1 is (0,10),(0,-10)