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Popular >

vertices x^2+4y^2=4

Solution

vertices

x^{2} + 4 y^{2} = 4

Solution

(2, 0), (- 2, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

x^{2} + 4 y^{2} = 4 :

Ellipse with center

(h, k) = (0, 0), a = 2, b = 1

(0 + 2, 0), (0 - 2, 0)

Refine

(2, 0), (- 2, 0)

Popular Examples

vertices ((x+5)^2)/9+(y-1)^2=1 vertices

\frac{( x + 5 ) ^{2}}{9} + (y - 1)^{2} = 1

vertices 8x^2+2y^2+16x=0 vertices

8 x^{2} + 2 y^{2} + 16 x = 0

vertices 9X^2+4Y^2=36 vertices

9 X^{2} + 4 Y^{2} = 36

vertices (x^2)/9+(y^2)/5 =1 vertices

\frac{x ^{2}}{9} + \frac{y ^{2}}{5} = 1

vertices x^2+1/3 y^2=1 vertices

x^{2} + \frac{1}{3} y^{2} = 1

Frequently Asked Questions (FAQ)

What is the vertices x^2+4y^2=4 ?
The vertices x^2+4y^2=4 is (2,0),(-2,0)