What is the vertices 9x^2-54x+4y^2=-45 ?

The vertices 9x^2-54x+4y^2=-45 is (3,3),(3,-3)

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vertices 9x^2-54x+4y^2=-45

vertices

9 x^{2} - 54 x + 4 y^{2} = - 45

(3, 3), (3, - 3)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

9 x^{2} - 54 x + 4 y^{2} = - 45 :

Ellipse with center

(h, k) = (3, 0), b = 3, a = 2

(3, 0 + 3), (3, 0 - 3)

Refine

(3, 3), (3, - 3)

3 x^{2} + y^{2} + 2 x - 6 y = 3

x^{2} + \frac{1}{3} y^{2} = x + y

25 x^{2} + 9 y^{2} - 100 x + 18 y - 116 = 0

10 x^{2} + 4 y^{2} + 2 x + 16 y = 144

9 x^{2} + 25 y^{2} + 18 x + 150 y + 9 = 0

What is the vertices 9x^2-54x+4y^2=-45 ?
The vertices 9x^2-54x+4y^2=-45 is (3,3),(3,-3)