What is the vertices 3x^2+y^2=84 ?

The vertices 3x^2+y^2=84 is (0,2sqrt(21)),(0,-2sqrt(21))

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vertices 3x^2+y^2=84

vertices

3 x^{2} + y^{2} = 84

(0, 221), (0, - 221)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

3 x^{2} + y^{2} = 84 :

Ellipse with center

(h, k) = (0, 0), b = 221, a = 27

(0, 0 + 221), (0, 0 - 221)

Refine

(0, 221), (0, - 221)

25 x^{2} + y^{2} - 100 x + 8 y + 91 = 0

9 x^{2} + 4 y^{2} + 72 x - 40 y + 208 = 0

\frac{( x + 2 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{25} = 1

3 x^{2} + 7 y^{2} - 12 x - 28 y + 19 = 0

x^{2} + 3 y^{2} + 2 x - 12 y + 10 = 0

What is the vertices 3x^2+y^2=84 ?
The vertices 3x^2+y^2=84 is (0,2sqrt(21)),(0,-2sqrt(21))