What is the vertices (x^2)/(100)+(y^2)/(36)=1 ?

The vertices (x^2)/(100)+(y^2)/(36)=1 is (10,0),(-10,0)

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vertices (x^2)/(100)+(y^2)/(36)=1

vertices

\frac{x ^{2}}{100} + \frac{y ^{2}}{36} = 1

(10, 0), (- 10, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

\frac{x ^{2}}{100} + \frac{y ^{2}}{36} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 10, b = 6

(0 + 10, 0), (0 - 10, 0)

Refine

(10, 0), (- 10, 0)

x^{2} + 3 y^{2} = 84

16 x^{2} + 25 y^{2} + 32 x - 384 = 0

\frac{( x - 2 ) ^{2}}{64} + \frac{( y + 4 ) ^{2}}{16} = 1

25 x^{2} + 16 y^{2} + 100 x - 96 y - 156 = 0

x^{2} + 4 y^{2} - 6 x - 16 y + 21 = 0

What is the vertices (x^2)/(100)+(y^2)/(36)=1 ?
The vertices (x^2)/(100)+(y^2)/(36)=1 is (10,0),(-10,0)