What is the vertices 4x^2+25y^2-50y=75 ?

The vertices 4x^2+25y^2-50y=75 is (5,1),(-5,1)

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vertices 4x^2+25y^2-50y=75

vertices

4 x^{2} + 25 y^{2} - 50 y = 75

(5, 1), (- 5, 1)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

4 x^{2} + 25 y^{2} - 50 y = 75 :

Ellipse with center

(h, k) = (0, 1), a = 5, b = 2

(0 + 5, 1), (0 - 5, 1)

Refine

(5, 1), (- 5, 1)

\frac{( x + 2 ) ^{2}}{4} + \frac{( y - 4 ) ^{2}}{16} = 1

\frac{x ^{2}}{3} + \frac{y ^{2}}{5} = 1

4 x^{2} + 9 y^{2} - 36 = 0

9 x^{2} + 49 y^{2} - 144 x + 490 y + 1360 = 0

4 x^{2} + 9 y^{2} - 24 x + 72 y + 144 = 0

What is the vertices 4x^2+25y^2-50y=75 ?
The vertices 4x^2+25y^2-50y=75 is (5,1),(-5,1)